-37x-12x^2+20=0

Solution for -37x-12x^2+20=0 equation:

-37x-12x^2+20=0

a = -12; b = -37; c = +20;
Δ = b2-4ac
Δ = -372-4·(-12)·20
Δ = 2329
The delta value is higher than zero, so the equation has two solutions
We use following formulas to calculate our solutions:
$x_{1}=\frac{-b-\sqrt{\Delta}}{2a}$
$x_{2}=\frac{-b+\sqrt{\Delta}}{2a}$

$x_{1}=\frac{-b-\sqrt{\Delta}}{2a}=\frac{-(-37)-\sqrt{2329}}{2*-12}=\frac{37-\sqrt{2329}}{-24}
$
$x_{2}=\frac{-b+\sqrt{\Delta}}{2a}=\frac{-(-37)+\sqrt{2329}}{2*-12}=\frac{37+\sqrt{2329}}{-24}
$